A (0.40-mathrm{m}) wire carries a current of (1.7 mathrm{~A}) and is at angle to a (0.20-mathrm{T}) uniform
Question:
A \(0.40-\mathrm{m}\) wire carries a current of \(1.7 \mathrm{~A}\) and is at angle to a \(0.20-\mathrm{T}\) uniform external magnetic field. What must be the angle between the wire and the magnetic field so that the field exerts a force of \(0.068 \mathrm{~N}\) on the wire?
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To find the angle between the wire and the magnetic field we can use the formula for ...View the full answer
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