Question: The center-to-center distance between a (200 mathrm{~g}) lead sphere and an (800 mathrm{~g}) lead sphere is (0.120 mathrm{~m}). A (1.00 mathrm{~g}) object is placed (0.0800

The center-to-center distance between a $200 \mathrm{~g}$ lead sphere and an $800 \mathrm{~g}$ lead sphere is $0.120 \mathrm{~m}$. A $1.00 \mathrm{~g}$ object is placed $0.0800 \mathrm{~m}$ from the center of the $800 \mathrm{~g}$ sphere along the line joining the centers of the two spheres.

(a) Ignoring all sources of gravitational force except the two spheres, calculate the gravitational force exerted on the object.

(b) Determine the gravitational potential energy per gram at the position of the object.

(c) How much work is needed to keep the object from getting closer than $0.0400 \mathrm{~m}$ from to the $800 \mathrm{~g}$ sphere?

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Lets solve each part of the problem step by step a Gravitational Force on the Object 1 Calculation of Gravitational Force The gravitational force F exerted on the 100 textg object by each sphere can b... View full answer

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