Question: a. Sketch, in the interval 2 x 2, the graph of y = 3 + 5 cosec x. b. Hence deduce the range

a. Sketch, in the interval −2π ≤ x ≤ 2π, the graph of y = 3 + 5 cosec x. 

b. Hence deduce the range of values of k for which the equation 3 + 5 cosec x = k has no solutions.

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a Given y 3 5 cosec x x fx 3 5 cosec x 628 2 6 2089 55 1009 5 821 4712... View full answer

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