AB is the vector 3i + tj + 5k, where t > 0. Given that |AB |

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AB is the vector −3i + tj + 5k, where t > 0. Given that |AB | = 5 √2, show that AB is parallel to 6i − 8j − 5/2tk.

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Pearson Edexcel A Level Mathematics Pure Mathematics Year 2

ISBN: 9781292183404

1st Edition

Authors: Greg Attwood, Jack Barraclough, Ian Bettison, David Goldberg, Alistair Macpherson, Joe Petran

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Question Posted: Aug 21, 2023 06:31 AM

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AB is the vector 3i + tj + 5k, where t > 0. Given that |AB |

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AB 52 9 t 25 50 t 16 ...View the full answer

Pearson Edexcel A Level Mathematics Pure Mathematics Year 2

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