Question: In this problem you will supply the missing steps in the derivation of the formula E singlet = E 1s + E 2s + J

In this problem you will supply the missing steps in the derivation of the formula Esinglet= E1s+ E2s+ J + K for the singlet level of the 1s12s1configuration of He.

a. Expand Equation (22.17) to obtain

1 [[ls(1)2s (2) + 2s (1) Is (2)](H1) [1s (1) 2s (2) + 2s (1) ls (2)]dT¡dr2 Esinglet [ls(1)2s (2) + 2s (1) Is (2)](Ĥ2)


b. Starting from the equations 1 2 Hˆ i1s(i) = E s1s(i) and Hˆ i 2s(i) = E s 2s(i), show that

singlet = E + E. jus02C)- [Ls1)25(2) + 25(1)ls(2)]| 4πεο μ-2) [1s (1) 2s (2) + 2s (1)1s(2)] d, dr,


c. Expand the previous equation using the definitions

1 [[ls(1)2s (2) + 2s (1) Is (2)](H1) [1s (1) 2s (2)

to obtain the desired result, Esinglet = E1s + E2s + J + K.

1 [[ls(1)2s (2) + 2s (1) Is (2)](H1) [1s (1) 2s (2) + 2s (1) ls (2)]dTdr2 Esinglet [ls(1)2s (2) + 2s (1) Is (2)](2) [1s (1) 2s (2) + 2s (1) 1s (2)]dTdr2 S/ [1s (1) 2s (2) + 2s (1) 1s (2)] 121(2) 4 -1 , [1s (1) 2s (2) + 2s (1) ls (2)]drdr2 singlet = E + E. jus02C)- [Ls1)25(2) + 25(1)ls(2)]| 4 -2) [1s (1) 2s (2) + 2s (1)1s(2)] d, dr,

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