The vapor pressure of various substances can be determined using effusion. In this process, the material of

Question:

The vapor pressure of various substances can be determined using effusion. In this process, the material of interest is placed in an oven (referred to as a Knudsen cell) and the mass of material lost through effusion is determined. The mass loss (Δm) is given by Δm = ZcAm Δt, where Zcis the collisional flux, A is the area of the aperture through which effusion occurs, m is the particle mass, and Δt is the time interval over which the mass loss occurs. This technique is quite useful for determining the vapor pressure of nonvolatile materials. A 1.00-g sample of UF6is placed in a Knudsen cell equipped with a 100.-μm-radius hole and heated to 18.2°C where the vapor pressure is 100. Torr.

a. The best scale in your lab has an accuracy of ±0.01 g. What is the minimum amount of time you must wait until the mass change of the cell can be determined by your balance?

b. How much UF6 will remain in the Knudsen cell after 5.00 min of effusion?

Calculation of the collisional flux proceeds as follows:

= 1.00 x 104 m 1m r = 100. Um 10 um

A = πr2 = π(1.00 × 10-4 m)2 = 3.14 × 10-8 m2

M = 0.352 kg mol -1 / N = 5.85 × 10-25 kg 

133.3 Pa 100. tor (27(5.85 x 10-25 1.33 x 10* Pa 1 torr kg)(138 x 10-23 J K- Z. (2rmkT)

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question

Physical Chemistry

ISBN: 978-0321812001

3rd edition

Authors: Thomas Engel, Philip Reid

Question Posted: