Question: The potential energy for a particle that can move along the x-axis is U = Ax 2 + B sin(x/L), where A, B, and L

The potential energy for a particle that can move along the x-axis is U = Ax2 + B sin(πx/L), where A, B, and L are constants. 

What is the force on the particle at

(a) x = 0,

(b) x = L/2,

(c) x = L?

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