Question: Evaluate the surface integral. S y 2 z 2 dS, S is the part of the cone y = x 2 + z 2

Evaluate the surface integral.

ʃʃS y2z2 dS,
S is the part of the cone y = √x2 + z2 given by 0 < y < 5

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Using a and z as parameters we have rxz xi x zjzk x z ... View full answer

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