Question: Evaluate the surface integral. S x dS, S is the surface y = x 2 + 4z, 0 < x < 1, 0 <
Evaluate the surface integral.
ʃʃS x dS,
S is the surface y = x2 + 4z, 0 < x < 1, 0 < z < 1
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Using a and z as parameters we have rxz x... View full answer
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