Question: Solve the Bernoulli equations. x 2 y + 2xy = y 3 HISTORICAL BIOGRAPHY James Bernoulli (1654-1705) A Bernoulli differential equation is of the form
Solve the Bernoulli equations.
x2y′ + 2xy = y3

HISTORICAL BIOGRAPHY James Bernoulli (1654-1705) A Bernoulli differential equation is of the form dy dx Observe that, if n = 0 or 1, the Bernoulli equation is linear. For other values of n, the substitution u = y-n transforms the Bernoulli equation into the linear equation du dx For example, in the equation + P(x)y= Q(x)y". or, equivalently, + (1 n)P(x)u = (1 n)Q(x). dy dx we have n = 2, so that u = y-2 = y and du/dx = -y- dy/dx. Then dy/dx = -y du/dx = u du/dx. Substitution into the original equation gives u = ex u -u -2 du dx du dx y = exy +u = ex. This last equation is linear in the (unknown) dependent variable u.
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ANSWER James Bernoulli was a Swiss mathematician born on December 27 1654 in Basel Switzerland He was the younger brother of the famous mathematician ... View full answer
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