Question: The iterated integral for evaluating D (r, , z) d r dr du over the given region D. D is the prism whose base

The iterated integral for evaluating ∫∫∫_Dƒ(r, θ, z) dθ r dr du over the given region D.

D is the prism whose base is the triangle in the xy-plane bounded by the y-axis and the lines y = x and y = 1 and whose top lies in the plane z = 2 - x. X N 2 z = 2 x y = x 1 y

X N 2 z = 2 x y = x 1 y

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The region D can be described as 0 4 0 r sec 0 z 2 r cos Therefore the iterated integral becomes D r ... View full answer

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