Question: Which function grows faster as n approaches infinity? Explain. f(n) = 7 g(n) = (n 1)!

Which function grows faster as n approaches infinity? Explain.


f(n) = 7 g(n) = (n 1)!

f(n) = 7 g(n) = (n 1)!

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As n approaches infinity the function fn 7n will grow much faster than the function gn n1 To see w... View full answer

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