The plane z = 0 defines the boundary between two dielectrics. For z < 0, r1
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The plane z = 0 defines the boundary between two dielectrics. For z < 0, ∈r1 = 9, ∈"r1 = 0, and μ1 = μ0. For z > 0, ∈'r2 = 3, ∈"r2 = 0, and μ2 = μ0. Let E+x1 = 10 cos(ωt − 15z) V/m and find
(a) ω;
(b) (S+1);
(c) (S−1);
(d) (S+2).
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a We have 0 1 r1 c 15 So 15c r1 15 3 10 8 9 15 10 9 s 1 b F...View the full answer
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