A laser is mounted as shown in the figure (distances d and h are given) above the axis of a converging lens with positive focal length f. The laser beam travels parallel to the axis of the lens.A large screen is placed at a distance d_s to the right of the lens. The laser beam passes through the lens and makes a dot on the screen at a distance h_s, measured upward from the axis of the lens. Assume that a positive value means that the dot is above the axis, while a negative value means that the dot is below the axis. part A

Find the distance h_s. Express your answer in terms of some or all of the variables d, h,f, and d_s. Note that not all of the variables may be required for the answer. Now consider a specific case. Let the laser be 50 centimeters to the left of the lens and at height 15 centimeters above the axis of the lens. The lens has focal length 30 centimeters, and the screen is 1 meter to the right of the lens. Part B What is the position h_s of the dot on the screen? Express your answer in centimeters, to two significant figures. Part c If the laser is moved farther from the lens, what happens to the dot on the screen? a)It moves up. b)It moves down. c)It does not move. Part D If the laser is moved up, farther above the axis of the lens, what happens to the dot on the screen? Assume that the ray still strikes the lens. a)It moves up. b)It moves down. c)It does not move.

Transcribed Image Text:

Laser h -P- Screen Laser h -P- Screen

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Part A h s hd s ff Notice that the sign of the height depe... View the full answer