A Pitot tube placed in front of a submarine moving horizontally in sea 16m below the water surface is connected to the two limbs of a U-tube mercury manometer. When the submarine is moving to a certain velocity, the manometer shows a deflection of 200mm. With a sketch of the system, compute the velocity of the submarine in km/hr. Given the specific gravity of mercury and seawater are 13.6 and 1.026, respectively.

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Depth of submarine is 16 m below thewater surface The... View the full answer