An oscillator with period 2.3 ms passes through equilibrium at t = 19.6 ms with velocity v

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An oscillator with period 2.3 ms passes through equilibrium at t = 19.6 ms with velocity v = -3.3 m/s. The equation of the oscillator's motion is x(t) =_____ cm cos ( ( _____ /s ) t +______) Fill in the blanks

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Physics

ISBN: 978-0321976444

5th edition

Authors: James S. Walker

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Posted Date: Jul 17, 2019 09:55 AM

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An oscillator with period 2.3 ms passes through equilibrium at t = 19.6 ms with velocity v

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Time period of the oscillator related to angular frequency as At equilibrium p... View the full answer

Physics

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