Question: How many milligrams of mercury(I) chloride (Hg 2 Cl 2 ) must be present in a 325 mL sample of water to give 4.20 ppm

How many milligrams of mercury(I) chloride (Hg2Cl2) must be present in a 325 mL sample of water to give 4.20 ppm (m/v) of Hg2Cl2?   

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To solve this problem we can use the definition of parts per million ppm which is calculated as foll... View full answer

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