$[06/12,7$:$18$pm$]$ Gayathri: $2.$ Keep the

L$=10$ cm$,$A$=7\mathrm{.}50$ cm

$2$

$.$ Slide the resistivity slider up and down. What happens to the resistance? What about the wire at the bottom of the screen? What do you think the black dots represent? $($Note that the dots cannot be electrons since the number of electrons cannot be larger when the resistivity is higher$).$ The resistance increases as it slides up$,$ and so do the black dots. It is ok if your values for the variables are within

$3\%$

$.$ You will have a hard time to set the exact value in the slider. Write down the value you used. Write the resistance value when:

$[2+1+2=5$

points

$]$

$1$

$=0\mathrm{.}10.$cm

and

$2$

$=0\mathrm{.}9.$cm

R

$1$

$=1$ohm;R

$2$

$=\mathrm{.}90$ohm

The black dots are: atoms Explain: Resistance of the wire increases when the length of the wire is increased as they are directly proportional to each other. $3.$ Set the resistivity

$1$

$=0\mathrm{.}50.$cm

and area

A$=7\mathrm{.}50.$cm

$2$

$.$ Move the length$-$slider up and down. What happens to the resistance and the wire? Why? Write the resistance for

L

$1$

$=3\mathrm{.}0$ cm

and

L

$2$

$=20$ cm$.[2+2+2=6$

points

$]$

R

$1$

$=50$R

$2$

$=$

Describe the dots of the wire

$[06/12,7$:$19$pm$]$ Gayathri: Set the resistivity

$=0\mathrm{.}50.$cm

and length

L$=10\mathrm{.}0.$cm

$.$ Change the 'area$-$slider'. What happens to the resistance and the wire? Why? Write the value of the resistance at

A

$1$

$=0\mathrm{.}5$ cm

$2$

and

A

$2$

$=15\mathrm{.}00$ cm

$2$

$.[2+2+2=6$

Points

$]$

$\backslash [$ R$\_\{1\}=\backslash$quad$,$ R$\_\{2\}=\backslash ]$ Describe the dots of the wire: How does the resistance change?

$[06/12,7$:$19$pm$]$ Gayathri: When the length

$($L$)$

of wire doubles and its cross$-$sectional area

$($A$)$

halves, what happens to the resistance

$()$

$?$ Give numeral examples from the simulation to support your answer. Include the values of

A

and

L

you used for calculation. Keep the resistivity,

$[06/12,7$:$20$pm$]$ Gayathri: onstant. $[1+2+2$

$=5$

Points$]$ Phys $1102$L Summer $20$

R$=$

L$=$

A $=$ Numerical example

$[06/12,7$:$20$pm$]$ Gayathri: $.$ When the length and area both double, what happens to the resistance of the wire? Explain with a numerical example. Keep the resistivity constant.

$[1+2+2=5$

Points

$]$

R$=$

L$=$

A$=$

Explain:: $7.$ When the resistivity

$($cm$)$

increases, the resistance

$[06/12,7$:$21$pm$]$ Gayathri: $1$ point$]8.$ What is the proportionality relationship between the following: $[6$ points$]($a$)$

and

R

$?$ b$)$

L

and

R

$?$ c$)$

A

and

R

$?9.$ From your observation of the dots in the simulation, the dots in the wire depends upon $[1$ point$]$