0.35 kg of air at a pressure of 150 kPa occupies 0.20 m³ and from this condition is compressed to 16 MPa accordingly to the law P*(V)128 = constant Determine change of internal energy of the air in kJ, the work is done on the air in kJ, the heat rejected by the air during compression in kJ Cp = 1005 kJ/kg K, Cv = 0718 kJ/kg K,R = 0287 kJ/kg K.
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