Question: 1 0 1 (1 point) Let V = span 0 , 1 , 0 . Peter asked his classmates if it was possible to find

1 0 1 (1 point) Let V = span 0 , 1 , 0 . Peter
1 0 1 (1 point) Let V = span 0 , 1 , 0 . Peter asked his classmates if it was possible to find avector 3 E [R3 such that V + {3} is not a 0 0 1 subspace of R3 . All of them told him that it wasn't possible, but they gave him very different reasons why. Whose explanation is correct? (Select all correct explanations. Recall: for an explanation to be correct, every part of the explanation must be correct.) 7 A. Bob said: No such 3 exists because V is a basis for R3. '7 B. Emma said: No such 5 exists because adding a vector 3 to V would produce a translated subspace. 7' G. Charles said: No such 3 exists because vector spaces are closed under addition and adding the set {3} will not make a difference. I D. Donna said: No such 3 exists because V is a subspace that contains 6 and so the set obtained by adding a vector 3 would still contain 6. 7' E. Alice said: No such 3 exists because V = [R3, so V + {3} = R3 + {E} = R3. 7 F. Frank said: No such 5 exists because V is already linearly dependent

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