Question: 1 0 . 2 0 av _ ( F ) = 4 0 cos 1 0 ^ ( 6 ) tV . bP _ (

10.20 av_(F)=40cos10^(6)tV.
bP_(dev)=\sum P_(()/(abs)).
cQ_(dev)=\sum Q_(abs ).
Figure P10.20
1 0 . 2 0 av _ ( F ) = 4 0 cos 1 0 ^ ( 6 ) tV .

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