Question: [1 2 0 3 1] 3 1 and let R= 0 0 1 4 2 00000 -1 -2 2 5 3] (20) 1. Let

[1 2 0 3 1] 3 1 and let R= 0 0

[1 2 0 3 1] 3 1 and let R= 0 0 1 4 2 00000 -1 -2 2 5 3] (20) 1. Let A = 1 You may assume that 20 4 1 10 4 2 answer R is the reduced row-echelon form of A, that is, R=rref(A). Using this fact, an the following questions. (a) Find a basis of the column space of A. (b) Find a basis of the row space of A. (c) Find a basis of the null space of A. (d) What is the rank of A? (e) What is the nullity of A?

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