1 = 2 1 Voz + 1 do, with a = 2x . Using the substitution 0 = sinh(u) , they first obtain de = p(u) du with p(u) = P and therefore B 1 = g(u) du with g (u) = and B = An antiderivative of g (u) is G(u) = u + sinh(2u) 2 , from which they conclude that the length / of the curve is sinh (27) + L, with L