Question: 1. 3 The vectors v1 = and v2 = , span a subspace V of the indicated Euclidean space. Find a basis for the orthogonal
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3 The vectors v1 = and v2 = , span a subspace V of the indicated Euclidean space. Find a basis for the orthogonal complement Vi of V. 3 9 13 24 (E Select the correct choice below and, if necessary, ll in the answer box(es) within your choice. {23' A- A basis tor the orthogonal complement Vi is { }. (Use a comma to separate vectors as needed.) {23' 3- There is no basis for the orthogonal complement Vi. A homogeneous second-order linear differential equation, two functions y1 and y2, and a pair of initial conditions are given. First verify that y1 and y2 are solutions of the differential equation. Then nd a particular solution of the form y = c1y1 + czyz that satisfies the given initial conditions Primes denote derivatives with respect to x. y\"+2y'+y=0;y1=e'x,y2=xe'x;y(0)=7,y'(0)= -6 Why is the function y1 = e"X a solution to the differential equation? Select the correct choice below and fill in the answer box to complete your choice. \":3 A- The function y1 = e'x is a solution because when the function and its indefinite integral, , are substituted into the equation, the result is a true statement. \":3 B- The function y1 = 6* is a solution because when the function, its rst derivative y1 ' = and its second derivative, y1 \" = , are substituted into the equation, the result is a true statement. Why is the function y2 = xe'x a solution to the differential equation? Select the correct choice below and ll in the answer box to complete your choice, \":3 A- The function y2 = xe'x is a solution because when the function and its indenite integral, , are substituted into the equation, the result is a true statement. B- The function y2 = xe' x is a solution because when the function, its derivative, y2' = , and its second derivative, y2 \" = , are substituted into the equation, the result is a true statement. The particular solution of the form y = c1y1 + c2y2 that satises the initial conditions y(0) = 7 and y'(0) = 6 is y =
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