$17-$ A crest vertical curve is designed as shown. The elevation $($ft$)$ of the PV$$ is most nearly:

A$.44+06\mathrm{.}00$

B$.41+92\mathrm{.}00$

$a=\frac{g_2-g_1}{2L_{\text{s}\text{t}\text{a}\text{t}}}=\frac{-3\mathrm{.}5-5}{2(1600)}=0$

C$.41+23\mathrm{.}00$

PVI or V

D$.40+75\mathrm{.}00$

Station $42+65$

$y_{PVC}=y_{\text{p}\text{V}\text{I}}-g_1(\frac{4(m)}{2})$

$V{e}_{sm}=V{I}_{\text{s}\text{t}\text{a}}-(\frac{4m}{2})$

Elevation $447$ ft