1. A circuit is depicted here with two switches. When a switch is open the wires are not connected, when it's closed a connection is formed. The three unknown resistors marked with R have the same value of resistance. Initially you close the first switch S and measure the current coming out of the battery. Then you open S again, and close the second switch S2. You find that in the second case the current coming out of the battery is four times greater than in the first case. Calculate the resistance R. Show all of your work. 2. Now you close both switches, and measure the voltage of the battery to be 14 Volts. Calculate the current coming out of the battery in this circuit. Show all of your work. 20 R E R 302 R 3. Now you close S and leave S2 open. Also, the 20 resistor burns out (wire breaks). Find the voltage drop across the resistor R which is in series with the 200 resistor. Explain. AVE IR; Rseries = R + R2 + ...; 1/Rparallel Pbattery ; Presistor = = 1R = (AV)/R = 1/R1 + 1/R2 + ... S 1 S 2