Question: 1. An object, 3.00 cm in height, is positioned 30.0 cm in front of a spherical refracting surface (n2 = 1.33), which is placed in

1. An object, 3.00 cm in height, is positioned 30.0 cm in front of a spherical refracting surface (n2 = 1.33), which is placed in air, as illustrated in the figure below. The radius of curvature of the spherical surface is 5.00 cm. Assuming paraxial rays: a. Determine the location of the image. b. Calculate the size of the resulting image. 2. Light from an object is refracted by a thin biconvex glass lens (nl = 1.5) with a focal length of 10.0 cm. a. If both surfaces have identical radii of curvature, what is their value? b. If an object is positioned 1.0 cm from the lens, determine the image distance. Describe the resulting image and illustrate it with a ray diagram. c. Now, imagine submerging this lens in a liquid whose refractive index is 1.42. What are the new focal length and image distance

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Answer 1 a The location of the image can be determined by tracing the refracted rays backward through the center of the sphere As shown in the figure ... View full answer

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