1) Compile, run, and study this C program:

#include

int main(void){

// note the array declaration format is slightly different from Java

int myInts[] = {0, 1, 2, 3, 4};

// declare an int pointer called pi and set it to point to the beginning of the array

// note that an array variable is a pointer to the beginning of the array

int *pi = myInts;

for(int counter = 0; counter

/* printf is also available in Java, but you may never have used it.

printf uses formatting codes like %p for pointer (addresses expressed in bytes in hexadecimal)

and %d for (decimal) int

*/

printf("Address %p: Value %d ", pi, *pi);

// incrementing a pointer changes it by the size of the type to which it points

pi += 1;

}

}

2) Add to this C program as follows:

a) Create an array of any five doubles and use a double pointer to iterate through it and print the addresses and values in the same way as the sample code iterates through the int array. The printf format code for a double is %f.

b) Do the same with an array of any five chars (for example, char myChars = {'J', 'o', 'h', 'n'}. The format code for a char is %c.

c) Add a multi-line comment (same syntax as Java) answering this question:

Suppose you had no other way to find out the size of an int, a double, or a byte (and note that, in C, these may actually vary between different compilers!) How could the output from your program help you answer these questions?