Question: 1. Consider the function: f:R R defined by f()2z +5 cos(3z). (a) Compute the values f (0) and f(1). Does f have a root in

 1. Consider the function: f:R R defined by f()2z +5 cos(3z).

1. Consider the function: f:R R defined by f()2z +5 cos(3z). (a) Compute the values f (0) and f(1). Does f have a root in the interval [0, 1]? (b) Apply the first three steps of the bisection method for f by hand. You can use a pocket calculator for computations. What is the absolute error for the solution at the end? (c) Use Matlab to approximate the root with an absolute error of e0.5-10-6. (d) Compute the values f(0) and f(2). Can you apply the bisection method on [0, 2]? With all the information learned so far about f, what can you say about the number of roots in the interval [0, 2]? please don't copy from an other expert

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