(1 point) Given a the vector equation r() = (3 + 5)i + (-5 -3)j + (3 + 2)k, rewrite this in terms of the symmetric equations for the line. (quotient involving x) (quotient involving y) = (quotient involving z) =(1 point) Suppose a line is given by the system of equations x = 3, y = -21, z = 2t -4. Then the vector and point that were used to define this line were U = , and P =(1 point) Rewrite the vector equation r() = (3 -4)i + (-3 -31)j + (3 + 4:)k as the corresponding parametric equations for the line. x(1) = y(!) = z(1) =(1 point) Find a vector equation with parameter : for the line through the point (8, 0, -6) and parallel to the vector 2i - 3j + 6k. Answer: r(t) =(1 point) Give a vector parametric equation for the line that passes through the point (-3, 0, 3), parallel to the line parametrizat L(t) =