(1 point) This question concerns block cipher modes. We will use a simple affine cipher, which...

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(1 point) This question concerns block cipher modes. We will use a simple affine cipher, which can be expressed in C as follows. char cipher(unsigned char block, char key) { return (key+11*block)%256; } Note that the block size is 8 bits, which is one byte (and one ASCII character). We will work with the fixed key 0x08. We now encrypt various plaintexts using modes for this cipher. In every case in which the mode requires an IV, the IV will be OxAA. In the case of CTR mode, we use a (nonce || counter) arrangement in which the nonce is the left 5 bits of OxAA and the counter is a 3 bit counter that begins at O. In all of the problems given below, one character is one block. Each character of the plaintext should be regarded as its corresponding ASCII code. a) Encrypt the plaintext "harpy" using CTR mode. Please enter your answer in hex. (Please do **not** enter an Ox, as this has been done.) Ox b) Encrypt the plaintext "helper" using ECB mode. Please enter your answer in hex. Ox c) Encrypt the plaintext "hinders" using CFB mode. Please enter your answer in hex. Ox d) Encrypt the plaintext "hung" using CBC mode. Please enter your answer in hex. Ox e) Encrypt the plaintext "hellos" using OFB mode. Please enter your answer in hex. Ox (1 point) This question concerns block cipher modes. We will use a simple affine cipher, which can be expressed in C as follows. char cipher(unsigned char block, char key) { return (key+11*block)%256; } Note that the block size is 8 bits, which is one byte (and one ASCII character). We will work with the fixed key 0x08. We now encrypt various plaintexts using modes for this cipher. In every case in which the mode requires an IV, the IV will be OxAA. In the case of CTR mode, we use a (nonce || counter) arrangement in which the nonce is the left 5 bits of OxAA and the counter is a 3 bit counter that begins at O. In all of the problems given below, one character is one block. Each character of the plaintext should be regarded as its corresponding ASCII code. a) Encrypt the plaintext "harpy" using CTR mode. Please enter your answer in hex. (Please do **not** enter an Ox, as this has been done.) Ox b) Encrypt the plaintext "helper" using ECB mode. Please enter your answer in hex. Ox c) Encrypt the plaintext "hinders" using CFB mode. Please enter your answer in hex. Ox d) Encrypt the plaintext "hung" using CBC mode. Please enter your answer in hex. Ox e) Encrypt the plaintext "hellos" using OFB mode. Please enter your answer in hex. Ox

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The exercise revolves around the application of various block cipher modes using an affine cipher function defined in C Before we begin with the encryption lets understand the cipher function provided ... View the full answer