Question: 1. Solve 1 au 2 102 u 1 au + r ar ar u(1, 0) = sin 0. = 0 for r < 1,

1. Solve 1 au 2 102 u 1 au + r ar

1. Solve 1 au 2 102 u 1 au + r ar ar u(1, 0) = sin 0. = 0 for r < 1, 1. Solve 1 au 2 102 u 1 au + r ar ar u(1, 0) = sin 0. = 0 for r < 1, 1. Solve 1 au 2 102 u 1 au + r ar ar u(1, 0) = sin 0. = 0 for r < 1, 1. Solve 1 au 2 102 u 1 au + r ar ar u(1, 0) = sin 0. = 0 for r < 1,

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