1) The checkage() method below prints an error message to signal an error. Define an exception illegalAgeException and re-write the code below to use exceptions instead of using error messages. Your code should try to recover from the exception in the main. import java.util.Scanner; int age public class ExceptionDemo { public static void main(String[] args) { //Reading user input Scanner sc = new Scanner (System.in); System.out.print("Please enter your age: "); sc.nextInt (); checkAge (age); } private static void checkAge (int age) { if (age>18){ System.out.println("You are authorized to view the page"); //other business logic } else System.out.println("You are not authorized to view page"); } }