$1.$ The $$while$$ statement$$while$(!(0$x$40$ & P$2$IN $))$ ;$$ will loop as long as:

a$)$ forever $$ b$)$ when bit $60$f $$P$2$IN $$is $1$ c$)$ when bit $60$f$$ P$2$IN$$ is $0$ d$)$ when$$ P$2$IN $=0$xFF