1

Use Newton's method with initial approximation x1 = -1 to find x2, the second approximation to the root of the equation x + x + 6 = 0. (Round your answer to four decimal places.)Part 2 of 8 f(Xn ) We know that Xn + 1 = Xn Therefore, f ' ( X n ) 6 An Xn+ 1 = Xp - 5 Xn Submit Skip (you cannot come back)Part 2 of 3 Xn 5 - Xn - 2 f(Xn ) Therefore, = Xn We have Xn + 1 = Xn f'(x) 5Xn - 1 X2 = 2 - 79 (rounded to six decimal places). Submit Skip (you cannot come back)