1. What effect does the vertical acceleration have on the horizontal velocity of the projectile? 2. Does your experimental value of the angle for maximum range agree with the theoretical value? If not, explain the possible cause. 3. Theoretically, for a given initial velocity, the maximum range is at the projection angle of 45. Then the curve of the range versus the projection angle must be symmetric about the angle 45". Namely, the range at 450+ A0 must be equal to the range at 45 A6, use equation (7) to prove this, namely, R(45+ A9) = R(45- A9)