$(1)x=0\mathrm{.}5m,x=0\mathrm{.}1m{T}_1=0,T_6=1\mathrm{.}0,\frac{d^{2}T}{d{x}^2}=-1$ Thomas$.(40)$

$x_n={}_n$

$x_i={}_i-\frac{e_i{x}_{i+1}}{{}_i},i=n-1,n-2,$cdots,$1$

${}_1=d_1$

${}_1=\frac{b_1}{{}_1}$

${}_i=d_i-\frac{c_i{e}_{i-1}}{{}_{i-1}},i=2,3,$cdots,$n$

${}_i=\frac{b_i-c_i{}_{i-1}}{{}_i},i=2,3,$cdots,$n$