Question: 10 2 . - 2 -2 - -6 - Let x(t) = to - 4+2 + t and y(t) = t2 - 6t + 3

 10 2 . - 2 -2 - -6 - Let x(t)

10 2 . - 2 -2 - -6 - Let x(t) = to - 4+2 + t and y(t) = t2 - 6t + 3 At t = 3, x(3) = 6 y(3) = 6 dac dt It =3 = 10 X dy dt It =3 = 4 X dy CT/ N dx t=3 = tangent slope = X speed (3) = 10.77 X Round to two decimal places

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