10. DETAILS Object Height. Suppose an object is thrown straight up from the ground. The height after t seconds is given by the formula h(t) = -2+3 + 89t2 + 205 (a) The time in seconds, rounded to 4 decimal places, when the object reached the highest point was O 205 s 29.6667 s O 66.75 s O None of the other answers O 22.25 s O O s (b) The height is maximized at the critical point x = a because the second derivative test found Of(a) was positive to the left of x = a and negative to the right Of (a) = 0 Of'(a) was negative to the left of x = a and positive to the right Of" (a ) = 0 Of" (a ) 0