Object Height. Suppose an object is thrown straight up from the ground. The height after t seconds is given by the formula h (t) = -2+ + 72+2 + 196 (a) The time in seconds when the object reached the highest point was Note: Round to 4 digits after the decimal point, if rounding is required O O s 196 s 0 54 s O 24 s O None of the other answers O 18 s (b) The height is maximized at the critical point x = a because the second derivative test found Of" (a) = 0 Of (a) = 0 Of" ( a ) > 0 Of'(a) was positive to the left of x = a and negative to the right O f'(a) was negative to the left of x = a and positive to the right Of" (a)