Object Height. Suppose an object is thrown straight up from the ground. The height after t seconds is given by the formula h (t) = -5+3 + 82+2 + 230 (a) The time in seconds, rounded to 4 decimal places, when the object reached the highest point was O 24.6 s O None of the other answers O 8.2 s O 10.9333 s O 230 s O O s (b) The height is maximized at the critical point x = a because the second derivative test found Of (a) was negative to the left of x = a and positive to the right Of" ( a ) > 0 Of" (a ) = 0 O f'(a) was positive to the left of x = a and negative to the right Of" ( a )