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nstructor-created question Question Help An experiment has a single factor with six groups and two values in each group. In determining the among-group variation, there are 5 degrees of freedom. In determining the within-group variation, there are 6 degrees of freedom. In determining the total variation, there are 11 degrees of freedom. Also, note that SSA = 180, SSW = 54, SST = 234, MSA = 36, MSW = 9, and FSTAT = 4. Complete parts (a) through (d). Click here to view page 1 of the F table. Click here to view page 2 of the F table. Click here to view page 3 of the F table. Click here to view page 4 of the F table. a. Construct the ANOVA summary table and fill in all values in the table. Degrees of Sum of Mean Square Source Freedom Squares (Variance) F Among groups Within groups Total (Your answers above must all be integers .) b. At the 0.05 level of significance, what is the upper-tail critical value from the F distribution? Fo.05 =(Round to two decimal places as needed.) c. State the decision rule for testing the null hypothesis that all six groups have equal population means. Reject Ho if d. What is your statistical decision? Since F STAT is than the upper-tall critical value, Ho . There is evidence to conclude there is a difference in the population means for the six groups. Enter your answer in the edit fields and then click Check Answer. Check Answer All parts showing Clear All