1.2 y ).1 12(x)=x -3 4-x-36 1 GV -0.1 One method for finding the limit as...

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1.2 y ).1 12(x)=√x -3 4-x-36 1 GV -0.1 One method for finding the limit as x->9 of the given function is to multiply the numerator and the denominator by (√+3). Doing so would produce (-9) 4(x-9)(√+3) How should someone finish the problem? The work thus far shows that x = 9 still causes the denominator to become zero, and so the limit as x->9 is "DNE." O The work thus far simplifies to 4(+3). for which the limit as x->9 is 1.2 y ).1 12(x)=√x -3 4-x-36 1 GV -0.1 One method for finding the limit as x->9 of the given function is to multiply the numerator and the denominator by (√+3). Doing so would produce (-9) 4(x-9)(√+3) How should someone finish the problem? The work thus far shows that x = 9 still causes the denominator to become zero, and so the limit as x->9 is "DNE." O The work thus far simplifies to 4(+3). for which the limit as x->9 is