Question: 13 The polynomial 6x3 + mx2 + nx - 5 has (x+1) as a factor. When the polynomial is divided by (x-1) there is a

 13 The polynomial 6x3 + mx2 + nx - 5 has

13 The polynomial 6x3 + mx2 + nx - 5 has (x+1) as a factor. When the polynomial is divided by (x-1) there is a remainder of -4. out of What is the polynomial? Select one: Oa. 6x3 + 8x2 - 3x - 5 O b. 6x3 - 3x2 + 8x - 5 O c. 6x3 - 8x2 + 3x - 5 O d. 6x3 + 3x2 - 8x - 5

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