Question: 17% Part (e) Young's modulus for bone is about Y = 1.6 x 1010 N/m. The tibia (shin bone) of a man is 0.2 m

17% Part (e) Young's modulus for bone is about Y =

17% Part (e) Young's modulus for bone is about Y = 1.6 x 1010 N/m. The tibia (shin bone) of a man is 0.2 m long and has an Stress average cross sectional area of 0.02 m2. What is the effective spring constant of the tibia in N/m? 50 0 0 A 17% Part (f) Given part (e), if a man weighs 750 N, how much is the tibia compressed if it supports half his weight? Give your answer in meters. d = m sin() cos() tan() JT 7 8 9 HOME cotan() asin() acos() E VV 4 5 6 atan() acotan() sinh() 1 2 3 cosh() tanh() cotanh() + 0 END Degrees O Radians VO BACKSPACE DEL CLEAR

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