Question: (1+x 2 ) dy/dx +2xy =f(x). ;y(0)=0 f(x) = { x. 0 -x. x>=1 f

(1+x2) dy/dx +2xy =f(x). ;y(0)=0

f(x) = { x. 0

-x. x>=1

(1+x2) dy/dx +2xy =f(x). ;y(0)=0f(x) = { x. 0 -x. x>=1 \f

\f

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