Question: 2. Given that (t) = 3t+ 2tj + 4tk, v(1) = 3 + 4j+2k, 7(1) = , where (t) is the acceleration function, (t)

2. Given that (t) = 3t+ 2tj + 4tk, v(1) = 3 + 4j+2k, 7(1) = , where (t) is the acceleration function, (t) is the velocity function, and 7(t) is the position function. Find the velocity and position functions. v (t) = f(t)dt = F(t) = f(t)dt =

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