22 Lead(II) iodide, PbI 2 , is a slightly solublesalt with a K SP value of9 8 x 10 9 The equation for itsdissociation in water is PbI 2 (s) Pb 2 (aq) 2I (aq) What is the molar solubility of PbI 2 in distilledwater 23 In the previous problem, you calculated the molarsolubility of PbI 2 in distilled ...

To solve these problems well use the concept of the solubility product constant K sp and the stoichi ...

22. Lead(II) iodide, PbI 2 , is a slightly solublesalt with a K SP value of9.8 x...

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Question:

22. Lead(II) iodide, PbI₂, is a slightly solublesalt with a K_SP value of9.8 x 10^-9. The equation for itsdissociation in water is

PbI₂(s) <----------> Pb²⁺(aq) + 2I^-(aq)

What is the molar solubility of PbI₂ in distilledwater?

23. In the previous problem, you calculated the molarsolubility of PbI₂ in distilled water. Nowconsider the molar solubility of PbI₂ in a1.50 M NaI solution. Sodium iodide is a freely solublesalt, and completely dissociates into its ions when dissolved inwater:

NaI(s) ==========> Na⁺(aq) + I^-(aq)

Therefore, a 1.50 M NaI solution is 1.50 M inNa⁺ and 1.50 M in I^-. Whenthe PbI₂ is dissolved in this solution, itestablishes its usual equilibrium:

PbI₂(s) <----------> Pb²⁺(aq) + 2I^-(aq) K_SP = 9.8 x 10^-9

But in the 1.50 M NaI solution, theI^- concentration will be 1.50 Meven before thePbI₂ dissociates. TheI^- formed in the dissociation ofPbI₂ will be in addition to thatalready present.

What is the molar solubility of PbI₂ in the1.50 M NaI solution?