Question: 9. What is the force on a 1.25 C charged quarter placed 15 cm from another quarter with -9.86 C of charge? F=_91-9 F-
9. What is the force on a 1.25 C charged quarter placed 15 cm from another quarter with -9.86 C of charge? F=_91-9 F- 1910) (1.25x105)(-9:46 X162) (0.15m)2 493N 10. How far away would the quarters in #9 be if the force on them is -19.7N? V= (9x10) (1.25 X 105) (-986162). 7.50 x 10 m V- -19.7N What do you notice about the distance ratio in #9 and # 10? What do you notice about the force ratio in #9 and #10? What happens to the force when the distance between two charged object doubles? (give a proportional answer such as "the force doubles or the force is one half, etc.) Using the symmetry of the arrangement, determine the direction of the electric field at the center of the square in Fig below. given that qa=qb=-1 uC qc=qd=1 uC. (b) Calculate the magnitude of the electric field at the location of q. given that the square is 5.00 cm on a side.
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In question 9 it seems like you are calculating the force between two charged quarters using Coulombs law The formula for the electrostatic force betw... View full answer
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