Question: 2-A particle is moving with the acceleration a(t) = t2 4t + 6. Let's denote the position of the particle by 5(t). If 5(0) =

2-A particle is moving with the acceleration a(t) = t2 4t

2-A particle is moving with the acceleration a(t) = t2 4t + 6. Let's denote the position of the particle by 5(t). If 5(0) = 0 and 5(1) = 5, what is 5(3)

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